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Ch. 4 - Applications of Derivatives
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077당신이 사용하는 게 아니라요?교과서 변경
모든 교과서Hass 15th EditionCh. 4 - Applications of Derivatives문제 4.4.39
4장, 문제 4.4.39

In Exercises 9–66, graph the function using appropriate methods from the graphing procedures presented just before Example 9, identifying the coordinates of any local extreme points and inflection points. Then find coordinates of absolute extreme points, if any.
39. y = 8 / (x² + 4) (Witch of Agnesi)

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Step 1: Analyze the function y = 8 / (x² + 4). Start by identifying its domain. Since the denominator x² + 4 is always positive and never zero, the function is defined for all real numbers x (domain: (-∞, ∞)).
Step 2: Find the first derivative y' to locate critical points and determine local extreme points. Use the quotient rule: if y = f(x)/g(x), then y' = (f'(x)g(x) - f(x)g'(x)) / [g(x)]². Here, f(x) = 8 and g(x) = x² + 4.
Step 3: Solve y' = 0 to find critical points. Set the numerator of the derivative equal to zero and solve for x. These x-values are potential locations for local maxima or minima. Verify these points by checking the sign of y' on intervals around each critical point.
Step 4: Find the second derivative y'' to determine concavity and locate inflection points. Use the quotient rule again to differentiate y'. Solve y'' = 0 to find potential inflection points, and verify by checking the sign of y'' on intervals around these points.
Step 5: Evaluate the function y at the critical points, inflection points, and endpoints (if applicable) to determine the coordinates of any absolute extreme points. Use this information to sketch the graph, noting the behavior of the function as x approaches ±∞ and the symmetry of the function (it is even, as y(x) = y(-x)).

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주요 개념

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Graphing Rational Functions

Graphing rational functions involves understanding their behavior based on the numerator and denominator. Key steps include identifying asymptotes, intercepts, and the overall shape of the graph. For the function y = 8 / (x² + 4), recognizing that the denominator never equals zero helps in determining the function's continuity and limits.
추천 영상:
5:53
Graph of Sine and Cosine Function

Local and Absolute Extrema

Local extrema refer to points where a function reaches a maximum or minimum value within a specific interval, while absolute extrema are the highest or lowest points over the entire domain. To find these points, one typically uses the first derivative test to identify critical points and the second derivative test to determine their nature.
추천 영상:
05:58
Finding Extrema Graphically

Inflection Points

Inflection points occur where the concavity of a function changes, which can be identified by analyzing the second derivative. For the function y = 8 / (x² + 4), finding inflection points involves setting the second derivative equal to zero and solving for x, indicating where the graph transitions from concave up to concave down or vice versa.
추천 영상:
04:50
Critical Points
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교과서 질문

Finding Indefinite Integrals


In Exercises 17–56, find the most general antiderivative or indefinite integral. You may need to try a solution and then adjust your guess. Check your answers by differentiation.


∫(3t² + t/2) dt

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The intensity of illumination at any point from a light source is proportional to the square of the reciprocal of the distance between the point and the light source. Two lights, one having an intensity eight times that of the other, are 6 m apart. How far from the stronger light is the total illumination least?

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Identifying Extrema


In Exercises 19–40:


a. Find the open intervals on which the function is increasing and those on which it is decreasing.


b. Identify the function’s local extreme values, if any, saying where they occur.


f(x) = x¹ᐟ³(x + 8)

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교과서 질문

Each of Exercises 67–88 gives the first derivative of a continuous function y=f(x). Find y'' and then use Steps 2–4 of the graphing procedure described in this section to sketch the general shape of the graph of f.

80. y' = 1 - cot²θ, for 0 < θ < π

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교과서 질문

Each of Exercises 67–88 gives the first derivative of a continuous function y=f(x). Find y'' and then use Steps 2–4 of the graphing procedure described in this section to sketch the general shape of the graph of f.

77. y' = cot(θ/2), for 0 < θ < 2π

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교과서 질문

Initial Value Problems


Solve the initial value problems in Exercises 71–90.


dy/dx = 1/x² + x, x > 0; y(2) = 1

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