Use the linear approximation (1 + x)ᵏ ≈ 1 + kx to find an approximation for the function f(x) for values of x near zero.

c. f(x) = 1/√(1 + x)

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Identify the function f(x) = 1/√(1 + x) and recognize that it can be rewritten as (1 + x)^(-1/2).

Use the linear approximation formula (1 + x)ᵏ ≈ 1 + kx, where k is the exponent of the expression. Here, k = -1/2.

Substitute k = -1/2 into the linear approximation formula to get (1 + x)^(-1/2) ≈ 1 - (1/2)x.

This approximation is valid for values of x near zero, providing a simpler expression to estimate f(x) without complex calculations.

Thus, the linear approximation for f(x) = 1/√(1 + x) near x = 0 is approximately 1 - (1/2)x.

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Linear Approximation

Linear approximation is a method used to estimate the value of a function near a given point using the tangent line at that point. For a function f(x), the linear approximation at x = a is given by L(x) = f(a) + f'(a)(x - a). This technique is particularly useful for simplifying complex functions near a specific point, often x = 0.

Derivative

The derivative of a function measures how the function's output value changes as its input changes. It is a fundamental concept in calculus, representing the slope of the tangent line to the function at any given point. For the function f(x) = 1/√(1 + x), finding the derivative is crucial for applying linear approximation, as it provides the rate of change needed for the approximation.

Binomial Approximation

The binomial approximation (1 + x)ᵏ ≈ 1 + kx is a simplification used when x is near zero. It is derived from the binomial series expansion and is particularly useful for approximating expressions involving powers of binomials. In the context of the given problem, this approximation helps simplify the function f(x) = 1/√(1 + x) by treating it as a binomial expression with k = -1/2.

Use the linear approximation (1 + x)ᵏ ≈ 1 + kx to find an approximation for the function f(x) for values of x near zero.c. f(x) = 1/√(1 + x)