130. Where does the periodic function f(x) = 2e^(sin(x/2)) take on its extreme values, and what are these values?

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Identify the function given: \(f(x) = 2e^{\sin(\frac{x}{2})}\), which is periodic due to the sine function inside the exponent.

To find the extreme values, compute the derivative \(f'(x)\) using the chain rule: \(f'(x) = 2e^{\sin(\frac{x}{2})} \cdot \cos(\frac{x}{2}) \cdot \frac{1}{2}\).

Set the derivative equal to zero to find critical points: \(f'(x) = 0 \Rightarrow 2e^{\sin(\frac{x}{2})} \cdot \cos(\frac{x}{2}) \cdot \frac{1}{2} = 0\). Since \(2e^{\sin(\frac{x}{2})} \neq 0\), this simplifies to \(\cos(\frac{x}{2}) = 0\).

Solve \(\cos(\frac{x}{2}) = 0\) for \(x\): \(\frac{x}{2} = \frac{\pi}{2} + k\pi\), where \(k\) is any integer, so \(x = \pi + 2k\pi\).

Evaluate \(f(x)\) at these critical points to find the extreme values: \(f(x) = 2e^{\sin(\frac{x}{2})}\), and since \(\sin(\frac{x}{2})\) oscillates between -1 and 1, the minimum and maximum values correspond to \(\sin(\frac{x}{2}) = -1\) and \(\sin(\frac{x}{2}) = 1\), respectively.

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주요 개념

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Periodic Functions

A periodic function repeats its values at regular intervals called periods. Understanding the period helps identify where the function's behavior repeats, which is essential for locating extreme values within one period and extending that knowledge to all periods.

Extreme Values of a Function

Extreme values are points where a function reaches local maxima or minima. These occur where the derivative is zero or undefined, and the function changes direction. Finding these points involves differentiating the function and solving for critical points.

Chain Rule and Differentiation of Composite Functions

The function f(x) = 2e^(sin(x/2)) is a composite function involving an exponential and a trigonometric function. Differentiating it requires applying the chain rule, which handles the derivative of a function inside another function, crucial for finding critical points.