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Ch. 7 - Transcendental Functions
Hass - Thomas' Calculus 15th Edition
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7장, 문제 7.6.57

Evaluate the integrals in Exercises 53–76.
57. ∫dx/(x√(25x²-2))

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1
Identify the integral to solve: \(\int \frac{dx}{x \sqrt{25x^{2} - 2}}\).
Recognize that the integrand contains a square root of a quadratic expression of the form \(a^{2}x^{2} - b^{2}\), which suggests using a trigonometric substitution to simplify the square root.
Set up the substitution by letting \(x = \frac{b}{a} \sec(\theta)\), where \(a = 5\) and \(b = \sqrt{2}\). So, let \(x = \frac{\sqrt{2}}{5} \sec(\theta)\).
Compute \(dx\) in terms of \(d\theta\) by differentiating the substitution: \(dx = \frac{\sqrt{2}}{5} \sec(\theta) \tan(\theta) d\theta\).
Rewrite the integral entirely in terms of \(\theta\), simplify the expression, and then integrate using trigonometric identities.

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

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Integrals containing expressions with square roots, such as √(25x² - 2), often require substitution or trigonometric methods to simplify the integrand. Recognizing the form under the radical helps determine the appropriate technique.
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