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Ch. 7 - Transcendental Functions
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077당신이 사용하는 게 아니라요?교과서 변경
7장, 문제 7.6.77

Evaluate the integrals in Exercises 77–90.
77. ∫dx/√(-x²+4x-3)

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Start by rewriting the expression under the square root to a more recognizable form. The integrand is \(\frac{1}{\sqrt{-x^{2} + 4x - 3}}\). Notice the quadratic inside the square root: \(-x^{2} + 4x - 3\).
Complete the square for the quadratic expression inside the square root. Factor out the negative sign first: \(-(x^{2} - 4x + 3)\). Then complete the square for \(x^{2} - 4x + 3\) by finding a perfect square trinomial.
Recall that \(x^{2} - 4x + 3 = (x - 2)^{2} - 1\) because \((x - 2)^{2} = x^{2} - 4x + 4\). Substitute this back to get \(-( (x - 2)^{2} - 1 ) = 1 - (x - 2)^{2}\) inside the square root.
Rewrite the integral as \(\int \frac{dx}{\sqrt{1 - (x - 2)^{2}}}\). This is a standard form that resembles the integral of \(\frac{1}{\sqrt{a^{2} - u^{2}}}\), which is related to the inverse sine function.
Use the substitution \(u = x - 2\), so \(du = dx\). The integral becomes \(\int \frac{du}{\sqrt{1 - u^{2}}}\). Recognize this as the integral of \(\frac{1}{\sqrt{1 - u^{2}}}\), whose antiderivative is \(\arcsin(u) + C\). Finally, substitute back \(u = x - 2\) to express the answer in terms of \(x\).

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Completing the Square

Completing the square is a technique used to rewrite quadratic expressions in the form ax² + bx + c as (x - h)² + k. This simplifies the integrand, especially when dealing with square roots of quadratic expressions, making it easier to identify the integral's form and apply appropriate methods.
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