For Exercises 127 and 128 find a function f satisfying each equation.
127. ∫₂ˣ √(f(t)) dt = x ln x

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Recognize that the problem gives an integral equation: \(\int_{2}^{x} \sqrt{f(t)} \, dt = x \ln x\). Our goal is to find the function \(f(x)\) that satisfies this equation.

Apply the Fundamental Theorem of Calculus by differentiating both sides of the equation with respect to \(x\). This gives: \(\frac{d}{dx} \int_{2}^{x} \sqrt{f(t)} \, dt = \frac{d}{dx} (x \ln x)\).

By the Fundamental Theorem of Calculus, the derivative of the integral with variable upper limit is the integrand evaluated at \(x\): \(\sqrt{f(x)} = \frac{d}{dx} (x \ln x)\).

Compute the derivative on the right side using the product rule: \(\frac{d}{dx} (x \ln x) = \ln x + 1\).

Set \(\sqrt{f(x)} = \ln x + 1\) and solve for \(f(x)\) by squaring both sides: \(f(x) = (\ln x + 1)^2\).

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주요 개념

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Fundamental Theorem of Calculus

This theorem links differentiation and integration, stating that if F(x) is defined as an integral of f(t) from a constant to x, then F'(x) = f(x). It allows us to find the original function inside an integral by differentiating the integral expression.

Differentiation of Functions Involving Logarithms

Understanding how to differentiate functions like x ln x is essential. Using the product rule, the derivative of x ln x is ln x + 1, which helps in equating the derivative of the integral to the function inside the integral.

Solving for the Unknown Function Inside an Integral

Given an integral equation, we use differentiation to isolate and solve for the unknown function f(t). This involves applying the Fundamental Theorem of Calculus and algebraic manipulation to express f(x) explicitly.

For Exercises 127 and 128 find a function f satisfying each equation.127. ∫₂ˣ √(f(t)) dt = x ln x