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Ch. 7 - Transcendental Functions
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077당신이 사용하는 게 아니라요?교과서 변경
7장, 문제 7.4.11

Solve the differential equation in Exercises 9–22.
11. (dy/dx) = e^(x-y)

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Rewrite the given differential equation \( \frac{dy}{dx} = e^{x - y} \) to separate the variables \( y \) and \( x \). Start by expressing \( e^{x - y} \) as \( e^x \cdot e^{-y} \), so the equation becomes \( \frac{dy}{dx} = e^x e^{-y} \).
Separate the variables by multiplying both sides by \( e^y \) and multiplying both sides by \( dx \), giving \( e^y dy = e^x dx \). This puts all \( y \)-terms on one side and all \( x \)-terms on the other.
Integrate both sides: integrate \( e^y \) with respect to \( y \) on the left, and integrate \( e^x \) with respect to \( x \) on the right. This yields \( \int e^y dy = \int e^x dx \).
After integrating, write the general solution including the constant of integration \( C \). The integrals of \( e^y \) and \( e^x \) are both \( e^y \) and \( e^x \) respectively, so the equation becomes \( e^y = e^x + C \).
If needed, solve explicitly for \( y \) by taking the natural logarithm of both sides, resulting in \( y = \ln(e^x + C) \), which represents the implicit or explicit general solution to the differential equation.

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

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