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Ch. 7 - Transcendental Functions
Hass - Thomas' Calculus 15th Edition
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7장, 문제 7.3.69

In Exercises 59–86, find the derivative of y with respect to the given independent variable.
69. y = 2^(sin 3t)

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1
Identify the function to differentiate: \(y = 2^{\sin(3t)}\). This is an exponential function where the base is a constant (2) and the exponent is a function of \(t\).
Recall the general rule for differentiating functions of the form \(a^{u(t)}\), where \(a\) is a constant and \(u(t)\) is a function of \(t\): the derivative is \(\frac{dy}{dt} = a^{u(t)} \cdot \ln(a) \cdot \frac{du}{dt}\).
Set \(u(t) = \sin(3t)\) and find its derivative \(\frac{du}{dt}\). Use the chain rule: the derivative of \(\sin(3t)\) is \(\cos(3t)\) multiplied by the derivative of \$3t$, which is 3. So, \(\frac{du}{dt} = 3 \cos(3t)\).
Apply the formula: \(\frac{dy}{dt} = 2^{\sin(3t)} \cdot \ln(2) \cdot 3 \cos(3t)\).
Write the final expression for the derivative as \(\frac{dy}{dt} = 3 \ln(2) \cdot 2^{\sin(3t)} \cdot \cos(3t)\), which expresses the rate of change of \(y\) with respect to \(t\).

비슷한 문제에 대한 검증된 영상 답변:

이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
3m

주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Chain Rule

The chain rule is used to differentiate composite functions. It states that the derivative of a function composed of another function is the derivative of the outer function evaluated at the inner function times the derivative of the inner function. For example, if y = f(g(t)), then dy/dt = f'(g(t)) * g'(t).
추천 영상:
05:02
Intro to the Chain Rule

Derivative of Exponential Functions with Variable Exponents

When differentiating functions like a^(u(t)), where the base a is constant and the exponent u(t) is a function of t, rewrite the function using exponentials and logarithms: a^(u) = e^(u ln a). Then apply the chain rule to differentiate e^(u ln a).
추천 영상:
04:50
Derivatives of General Exponential Functions

Derivative of Trigonometric Functions

The derivative of sine and cosine functions are fundamental in calculus. Specifically, d/dt[sin(kt)] = k cos(kt), where k is a constant. This rule is essential when differentiating expressions like sin(3t) inside the exponent.
추천 영상:
06:35
Derivatives of Other Inverse Trigonometric Functions