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Ch. 8 - Techniques of Integration
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077당신이 사용하는 게 아니라요?교과서 변경
8장, 문제 8.2.28

Evaluate the integrals in Exercises 25–30 by using a substitution prior to integration by parts.
∫ ln(x + x²) dx

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Start by examining the integral \(\int \ln(x + x^{2}) \, dx\). Notice that the argument of the logarithm can be factored to simplify the expression inside the logarithm.
Factor the expression inside the logarithm: \(x + x^{2} = x(1 + x)\). Use the logarithm property \(\ln(ab) = \ln a + \ln b\) to rewrite the integral as \(\int \ln x + \ln(1 + x) \, dx\).
Split the integral into two separate integrals: \(\int \ln x \, dx + \int \ln(1 + x) \, dx\). This makes the problem easier to handle by dealing with each term individually.
For each integral, use integration by parts. Recall the formula for integration by parts: \(\int u \, dv = uv - \int v \, du\). Choose \(u\) to be the logarithmic function (e.g., \(u = \ln x\) or \(u = \ln(1 + x)\)) and \(dv\) to be \(dx\).
Compute \(du\) and \(v\) for each integral: For \(u = \ln x\), \(du = \frac{1}{x} dx\); for \(dv = dx\), \(v = x\). Similarly, for \(u = \ln(1 + x)\), \(du = \frac{1}{1 + x} dx\); for \(dv = dx\), \(v = x\). Then apply the integration by parts formula to each integral separately.

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Substitution Method

The substitution method simplifies integrals by changing variables to transform the integral into a more manageable form. It involves choosing a substitution u = g(x) that simplifies the integrand, then rewriting the integral in terms of u and du. This technique is often used to prepare an integral for further methods like integration by parts.
추천 영상:
07:33
Euler's Method

Integration by Parts

Integration by parts is a technique based on the product rule for differentiation. It transforms the integral of a product of functions into simpler integrals using the formula ∫u dv = uv - ∫v du. Choosing u and dv wisely is crucial to simplify the integral effectively.
추천 영상:
06:18
Integration by Parts for Definite Integrals

Logarithmic Integration

Integrals involving logarithmic functions often require special techniques, such as substitution or integration by parts, because logarithms do not have elementary antiderivatives in simple form. Recognizing how to manipulate the argument of the logarithm can simplify the integral and make it solvable.
추천 영상:
7:30
Logarithms Introduction