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Ch. 8 - Techniques of Integration
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077당신이 사용하는 게 아니라요?교과서 변경
8장, 문제 8.6.52

Evaluate the integrals in Exercises 51–56 by making a substitution (possibly trigonometric) and then applying a reduction formula.
∫ csc³(√θ) / √θ dθ

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1
Start by making the substitution to simplify the integral. Let \( u = \sqrt{\theta} \), which implies \( \theta = u^2 \). Then, differentiate both sides to find \( d\theta \): \( d\theta = 2u \, du \).
Rewrite the integral in terms of \( u \). Since \( \sqrt{\theta} = u \), the integral becomes \( \int \frac{\csc^3(u)}{u} d\theta = \int \frac{\csc^3(u)}{u} \cdot 2u \, du = 2 \int \csc^3(u) \, du \). Notice how the \( u \) terms cancel out.
Focus now on evaluating \( \int \csc^3(u) \, du \). This is a standard integral that can be solved using a reduction formula or by expressing \( \csc^3(u) \) as \( \csc(u) \cdot \csc^2(u) \) and using integration by parts.
Recall the reduction formula for \( \int \csc^n(u) \, du \) when \( n \) is an odd integer: \[ \int \csc^n(u) \, du = -\frac{\csc^{n-2}(u) \cot(u)}{n-1} + \frac{n-2}{n-1} \int \csc^{n-2}(u) \, du \]. Apply this formula with \( n=3 \) to reduce the integral to a simpler form.
After applying the reduction formula, integrate the resulting simpler integral(s) and then substitute back \( u = \sqrt{\theta} \) to express the answer in terms of \( \theta \).

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Trigonometric Substitution

Trigonometric substitution involves replacing a variable or expression with a trigonometric function to simplify integrals, especially those involving roots or powers of trigonometric functions. It helps transform complicated integrals into more manageable forms by leveraging trigonometric identities.
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6:04
Introduction to Trigonometric Functions

Reduction Formulas

Reduction formulas are recursive relationships that express an integral with a higher power in terms of an integral with a lower power. They simplify the evaluation of integrals involving powers of trigonometric functions by breaking them down step-by-step.
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가이드 코스
5:59
Recursive Formulas

Integration of Powers of Cosecant

Integrating powers of cosecant functions often requires using identities and reduction formulas due to their complexity. Understanding how to manipulate expressions like csc³(x) and apply appropriate substitutions is essential for solving such integrals.
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05:42
Example 6: Integral of Secant & Cosecant