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Ch. 8 - Techniques of Integration
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077당신이 사용하는 게 아니라요?교과서 변경
8장, 문제 8.3.50

Evaluate the integrals in Exercises 33–52.
∫ 8 cot⁴(t) dt

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Recall that \( \cot(t) = \frac{\cos(t)}{\sin(t)} \) and that powers of cotangent can be expressed in terms of cosecant using the identity \( \cot^2(t) = \csc^2(t) - 1 \). This will help simplify the integral.
Rewrite \( \cot^4(t) \) as \( (\cot^2(t))^2 \), then use the identity to express it in terms of \( \csc^2(t) \): \[ 8 \cot^4(t) = 8 (\cot^2(t))^2 = 8 (\csc^2(t) - 1)^2 \]
Expand the square to get: \[ 8 (\csc^4(t) - 2 \csc^2(t) + 1) \] which breaks the integral into three simpler integrals:
Set up the integral as the sum of three integrals: \[ \int 8 \cot^4(t) \, dt = \int 8 \csc^4(t) \, dt - \int 16 \csc^2(t) \, dt + \int 8 \, dt \]
Evaluate each integral separately: - For \( \int \csc^2(t) \, dt \), recall that the derivative of \( -\cot(t) \) is \( \csc^2(t) \). - For \( \int \csc^4(t) \, dt \), use reduction formulas or rewrite \( \csc^4(t) = (\csc^2(t))^2 \) and express in terms of \( \cot(t) \) and \( \csc(t) \) to integrate. - The integral of a constant is straightforward. Combine all results to express the final integral.

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주요 개념

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Trigonometric Identities

Trigonometric identities are equations involving trigonometric functions that hold true for all values within their domains. For integrating powers of cotangent, identities like cot²(t) = csc²(t) - 1 help simplify the integrand into more manageable terms.
추천 영상:
7:17
Verifying Trig Equations as Identities

Integration of Powers of Trigonometric Functions

Integrating powers of trigonometric functions often requires rewriting the integrand using identities or reduction formulas. For cotangent raised to a power, expressing cot⁴(t) in terms of cot²(t) and then using substitution or known integrals facilitates the evaluation.
추천 영상:
가이드 코스
6:04
Introduction to Trigonometric Functions

Substitution Method in Integration

The substitution method involves changing variables to simplify an integral. When integrating functions like cotangent powers, substituting u = cot(t) or using related expressions can transform the integral into a polynomial form, making it easier to solve.
추천 영상:
07:33
Euler's Method