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Ch. 9 - First-Order Differential Equations
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077당신이 사용하는 게 아니라요?교과서 변경
9장, 문제 9.2.6

First-Order Linear Equations
Solve the differential equations in Exercises 1–14.


(1+x)y' + y = √x

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Rewrite the given differential equation \((1+x)y' + y = \sqrt{x}\) in the standard linear form \(y' + P(x)y = Q(x)\) by dividing both sides by \((1+x)\), resulting in \(y' + \frac{1}{1+x}y = \frac{\sqrt{x}}{1+x}\).
Identify the integrating factor \(\mu(x)\), which is given by \(\mu(x) = e^{\int P(x)\,dx}\). Here, \(P(x) = \frac{1}{1+x}\), so compute \(\mu(x) = e^{\int \frac{1}{1+x} dx}\).
Calculate the integral \(\int \frac{1}{1+x} dx\), which is \(\ln|1+x|\), and thus the integrating factor becomes \(\mu(x) = e^{\ln|1+x|} = |1+x|\). Since \(1+x > 0\) for the domain of interest, we can write \(\mu(x) = 1+x\).
Multiply the entire differential equation by the integrating factor \(\mu(x) = 1+x\) to get \((1+x)y' + y = \sqrt{x}\) multiplied by \(1+x\), which simplifies back to the left side being the derivative of \(\mu(x)y\), i.e., \(\frac{d}{dx}[(1+x)y] = (1+x) \cdot \frac{\sqrt{x}}{1+x} = \sqrt{x}\).
Integrate both sides with respect to \(x\): \(\int \frac{d}{dx}[(1+x)y] dx = \int \sqrt{x} dx\). This gives \((1+x)y = \int x^{1/2} dx + C\). Then solve for \(y\) by dividing both sides by \((1+x)\).

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

First-Order Linear Differential Equations

A first-order linear differential equation has the form y' + P(x)y = Q(x). It involves the first derivative of the unknown function and can be solved using an integrating factor. Recognizing this form is essential to apply the correct solution method.
추천 영상:
07:39
Classifying Differential Equations

Integrating Factor Method

The integrating factor is a function, usually denoted μ(x), used to multiply both sides of a linear differential equation to make the left side an exact derivative. It is found by μ(x) = e^(∫P(x)dx), enabling straightforward integration to solve for y.
추천 영상:
07:33
Euler's Method

Solving for y after Integration

After multiplying by the integrating factor, the equation becomes d/dx[μ(x)y] = μ(x)Q(x). Integrating both sides with respect to x and then isolating y gives the general solution. This step requires careful integration and algebraic manipulation.
추천 영상:
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Integration by Parts for Definite Integrals