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Ch. 9 - First-Order Differential Equations
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077당신이 사용하는 게 아니라요?교과서 변경
9장, 문제 9.2.24

Is either of the following equations correct? Give reasons for your answers.


a. (1/cosx) ∫ cos x dx = tan x + C
b. (1/cosx) ∫ cos x dx = tan x + C / cos x

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Start by evaluating the integral \( \int \cos x \, dx \). Recall that the integral of \( \cos x \) is \( \sin x + C \), where \( C \) is the constant of integration.
Rewrite the left side of both equations by substituting the integral: \( \frac{1}{\cos x} \int \cos x \, dx = \frac{1}{\cos x} (\sin x + C) \). This simplifies to \( \frac{\sin x}{\cos x} + \frac{C}{\cos x} \).
Recognize that \( \frac{\sin x}{\cos x} = \tan x \), so the expression becomes \( \tan x + \frac{C}{\cos x} \).
Compare this result with the right sides of the given equations: (a) \( \tan x + C \) and (b) \( \tan x + \frac{C}{\cos x} \). Notice that the constant term in (a) does not match the derived expression, while (b) matches exactly.
Conclude that equation (b) is correct because it properly accounts for the constant of integration divided by \( \cos x \), whereas equation (a) incorrectly treats the constant as a simple additive constant without division by \( \cos x \).

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주요 개념

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Integration of Basic Trigonometric Functions

Understanding how to integrate basic trigonometric functions like cos x is essential. The integral of cos x with respect to x is sin x plus a constant of integration, C. This fundamental fact helps evaluate the given expressions correctly.
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After integrating, it is important to correctly manipulate algebraic expressions, especially when dividing by functions like cos x. This includes distributing division over sums and understanding how constants of integration behave under division.
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