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Ch. 1 - Equations and Inequalities
Blitzer - College Algebra 8th Edition
Blitzer8th EditionCollege AlgebraISBN: 9780136970514당신이 사용하는 게 아니라요?교과서 변경
2장, 문제 17

Solve each equation. Then state whether the equation is an identity, a conditional equation, or an inconsistent equation. 7(x-4) = x + 2

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Start by expanding the left side of the equation using the distributive property: \(7(x - 4) = 7 \cdot x - 7 \cdot 4\) which simplifies to \(7x - 28\).
Rewrite the equation with the expanded left side: \(7x - 28 = x + 2\).
Next, get all the variable terms on one side and the constants on the other side. Subtract \(x\) from both sides to isolate the variable terms: \(7x - x - 28 = 2\) which simplifies to \(6x - 28 = 2\).
Then, add 28 to both sides to move the constant term: \(6x - 28 + 28 = 2 + 28\) which simplifies to \(6x = 30\).
Finally, solve for \(x\) by dividing both sides by 6: \(x = \frac{30}{6}\). After finding \(x\), analyze the solution to determine if the equation is an identity (true for all \(x\)), a conditional equation (true for specific \(x\)), or inconsistent (no solution).

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