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Ch. 1 - Equations and Inequalities
Blitzer - College Algebra 8th Edition
Blitzer8th EditionCollege AlgebraISBN: 9780136970514당신이 사용하는 게 아니라요?교과서 변경
2장, 문제 75

In Exercises 71–78, solve each equation. Then determine whether the equation is an identity, a conditional equation, or an inconsistent equation. 10x + 3 = 8x + 3

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Start by writing down the given equation: \(10x + 3 = 8x + 3\).
To isolate the variable terms on one side, subtract \$8x$ from both sides: \(10x + 3 - 8x = 8x + 3 - 8x\), which simplifies to \(2x + 3 = 3\).
Next, subtract 3 from both sides to isolate the term with \(x\): \(2x + 3 - 3 = 3 - 3\), which simplifies to \(2x = 0\).
Now, solve for \(x\) by dividing both sides by 2: \(\frac{2x}{2} = \frac{0}{2}\), which simplifies to \(x = 0\).
Finally, analyze the solution: since you found a specific value for \(x\), the equation is a conditional equation (true only for \(x = 0\)).

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주요 개념

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