Use the Leading Coefficient Test to determine the end behavior of the graph of the polynomial function.
Ch. 3 - Polynomial and Rational Functions

4장, 문제 23
Use the vertex and intercepts to sketch the graph of each quadratic function. Give the equation of the parabola's axis of symmetry. Use the graph to determine the function's domain and range. f(x)=2(x+2)2−1
검증된 단계별 안내1
Identify the given quadratic function: \(f(x) = 2(x+2)^2 - 1\). Notice it is in vertex form, \(f(x) = a(x-h)^2 + k\), where \((h, k)\) is the vertex.
Determine the vertex by comparing: here, \(h = -2\) and \(k = -1\), so the vertex is at \((-2, -1)\).
Find the axis of symmetry, which is the vertical line passing through the vertex: \(x = h\), so the axis of symmetry is \(x = -2\).
Calculate the y-intercept by evaluating \(f(0)\): substitute \(x=0\) into the function to find the point where the graph crosses the y-axis.
Determine the x-intercepts by setting \(f(x) = 0\) and solving for \(x\): solve the equation \(2(x+2)^2 - 1 = 0\) to find the points where the graph crosses the x-axis.

비슷한 문제에 대한 검증된 영상 답변:
이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
5m주요 개념
질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.
Vertex Form of a Quadratic Function
The vertex form of a quadratic function is f(x) = a(x - h)^2 + k, where (h, k) is the vertex of the parabola. This form makes it easy to identify the vertex, which is the highest or lowest point on the graph depending on the sign of a. For f(x) = 2(x+2)^2 - 1, the vertex is at (-2, -1).
추천 영상:
Vertex Form
Axis of Symmetry
The axis of symmetry is a vertical line that passes through the vertex of the parabola, dividing it into two mirror-image halves. Its equation is x = h, where h is the x-coordinate of the vertex. For the given function, the axis of symmetry is x = -2.
추천 영상:
Properties of Parabolas
Domain and Range of Quadratic Functions
The domain of any quadratic function is all real numbers since the parabola extends infinitely left and right. The range depends on the vertex and the direction the parabola opens. Since a = 2 > 0, the parabola opens upward, so the range is all y-values greater than or equal to the vertex's y-coordinate, i.e., y ≥ -1.
추천 영상:
Domain & Range of Transformed Functions
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