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Ch. 5 - Systems of Equations and Inequalities
Blitzer - College Algebra 8th Edition
Blitzer8th EditionCollege AlgebraISBN: 9780136970514당신이 사용하는 게 아니라요?교과서 변경
6장, 문제 13

In Exercises 5–18, solve each system by the substitution method. 2x + 5y = - 4 3x - y = 11
Two linear equations for solving a system by substitution method in college algebra.

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1
Start with the given system of equations: 2x+5y=-43x-y=11.
Solve one of the equations for one variable in terms of the other. For example, solve the second equation for y: 3x - y = 11 becomes y = 3x - 11.
Substitute the expression for y from step 2 into the first equation: replace y in 2x + 5y = -4 with 3x - 11 to get 2x + 5(3x - 11) = -4.
Simplify and solve the resulting equation for x. This will give you the value of x in terms of numbers.
Substitute the value of x back into the expression for y found in step 2 to find the corresponding value of y. This completes the solution to the system.

비슷한 문제에 대한 검증된 영상 답변:

이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
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주요 개념

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