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Ch. 5 - Systems of Equations and Inequalities
Blitzer - College Algebra 8th Edition
Blitzer8th EditionCollege AlgebraISBN: 9780136970514당신이 사용하는 게 아니라요?교과서 변경
6장, 문제 11

In Exercises 5–18, solve each system by the substitution method. 5x + 2y = 0 x - 3y = 0
Two linear equations for a system: 5x + 2y = 0 and x - 3y = 0.

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1
Start with the given system of equations: 5x+2y=0x-3y=0.
Solve one of the equations for one variable in terms of the other. For example, from the second equation x - 3y = 0, solve for x: x = 3y.
Substitute the expression for x from step 2 into the first equation: replace x with 3y in 5x + 2y = 0 to get 5(3y) + 2y = 0.
Simplify the resulting equation and solve for y: 15y + 2y = 0 which simplifies to 17y = 0, then solve for y.
Use the value of y found in step 4 and substitute it back into the expression for x from step 2 to find the value of x.

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이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
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주요 개념

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