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Ch. 7 - Conic Sections
Blitzer - College Algebra 8th Edition
Blitzer8th EditionCollege AlgebraISBN: 9780136970514당신이 사용하는 게 아니라요?교과서 변경
모든 교과서Blitzer 8th EditionCh. 7 - Conic Sections문제 53
8장, 문제 53

In Exercises 51–56, graph each relation. Use the relation's graph to determine its domain and range. x29+y216=1\(\frac{x^2}{9}\) + \(\frac{y^2}{16}\) = 1

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Recognize that the given equation \(\frac{x^2}{9} + \frac{y^2}{16} = 1\) represents an ellipse centered at the origin, where the denominators 9 and 16 correspond to the squares of the ellipse's semi-axes lengths.
Identify the lengths of the semi-major and semi-minor axes: \(a = 3\) (since \(9 = 3^2\)) and \(b = 4\) (since \(16 = 4^2\)). This means the ellipse stretches 3 units along the x-axis and 4 units along the y-axis.
To graph the ellipse, plot the points \((\pm 3, 0)\) and \((0, \pm 4)\) on the coordinate plane, which are the vertices of the ellipse along the x- and y-axes respectively.
Use the ellipse equation to express \(y\) in terms of \(x\) to understand the shape: rearrange to \(\frac{y^2}{16} = 1 - \frac{x^2}{9}\), then multiply both sides by 16 to get \(y^2 = 16 \left(1 - \frac{x^2}{9}\right)\), and finally take the square root to find \(y = \pm 4 \sqrt{1 - \frac{x^2}{9}}\).
Determine the domain and range from the ellipse: since \(x^2/9 \leq 1\), the domain is \(-3 \leq x \leq 3\); similarly, since \(y^2/16 \leq 1\), the range is \(-4 \leq y \leq 4\).

주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Equation of an Ellipse

An ellipse is a set of points where the sum of distances to two fixed points (foci) is constant. Its standard form equation is (x²/a²) + (y²/b²) = 1, where a and b are the lengths of the semi-major and semi-minor axes. This equation describes the shape and size of the ellipse on the coordinate plane.
추천 영상:
5:30
Foci and Vertices of an Ellipse

Domain and Range of a Relation

The domain of a relation is the set of all possible x-values, while the range is the set of all possible y-values. For graphs like ellipses, these correspond to the horizontal and vertical extents of the curve. Determining domain and range involves identifying the minimum and maximum values x and y can take.
추천 영상:
4:22
Domain & Range of Transformed Functions

Graphing Conic Sections

Graphing conic sections involves plotting points that satisfy their equations and understanding their geometric properties. For ellipses, the graph is symmetric about both axes, with intercepts at ±a on the x-axis and ±b on the y-axis. Recognizing these features helps in sketching the graph accurately.
추천 영상:
3:08
Geometries from Conic Sections
관련 실천
교과서 질문

In Exercises 51–56, graph each relation. Use the relation's graph to determine its domain and range. y216−x29=1\(\frac{y^2}{16}\) - \(\frac{x^2}{9}\) = 1

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교과서 질문

Identify each equation without completing the square.

9x2+25y2−54x−200y+256=09x^2+25y^2-54x-200y+256=0

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교과서 질문

Convert each equation to standard form by completing the square on x and y. Then graph the ellipse and give the location of its foci. 9x2 +25y² - 36x + 50y – 164 = 0

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교과서 질문

Identify each equation without completing the square.

9x2+4y2−36x+8y+31=09x^2+4y^2-36x+8y+31=0

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교과서 질문

Convert each equation to standard form by completing the square on x and y. Then graph the ellipse and give the location of its foci. 9x² + 16y² – 18x + 64y – 71 = 0

1024
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교과서 질문

In Exercises 51–56, graph each relation. Use the relation's graph to determine its domain and range. x29−y216=1\(\frac{x^2}{9}\) - \(\frac{y^2}{16}\) = 1

25
views