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Ch. P - Fundamental Concepts of Algebra
Blitzer - College Algebra 8th Edition
Blitzer8th EditionCollege AlgebraISBN: 9780136970514당신이 사용하는 게 아니라요?교과서 변경
1장, 문제 39

In Exercises 15–58, find each product. (1−y5)(1+y5)

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1
Recognize that the given expression (1−y^5)(1+y^5) is a product of two binomials in the form (a−b)(a+b). This is a difference of squares formula.
Recall the difference of squares formula: (a−b)(a+b) = a^2 − b^2. Here, a = 1 and b = y^5.
Substitute the values of a and b into the formula: a^2 − b^2 becomes 1^2 − (y^5)^2.
Simplify each term: 1^2 simplifies to 1, and (y^5)^2 simplifies to y^(5×2) = y^10.
Combine the simplified terms to get the final expression: 1 − y^10.

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이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Difference of Squares

The difference of squares is a fundamental algebraic identity that states that for any two terms a and b, the expression (a - b)(a + b) equals a² - b². This identity is crucial for simplifying expressions that are structured as a product of a sum and a difference, allowing for easier calculations and factorizations.
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Factoring Polynomials

Factoring polynomials involves rewriting a polynomial as a product of its factors, which can simplify expressions and solve equations. In the context of the given expression, recognizing the structure as a difference of squares allows for straightforward factoring, leading to a more manageable form.
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Introduction to Factoring Polynomials

Algebraic Manipulation

Algebraic manipulation refers to the techniques used to rearrange and simplify algebraic expressions. This includes applying identities, combining like terms, and distributing products. Mastery of these techniques is essential for effectively solving algebraic problems and understanding the relationships between different algebraic forms.
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Introduction to Algebraic Expressions