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Ch. P - Fundamental Concepts of Algebra
Blitzer - College Algebra 8th Edition
Blitzer8th EditionCollege AlgebraISBN: 9780136970514당신이 사용하는 게 아니라요?교과서 변경
1장, 문제 71

In Exercises 65–92, factor completely, or state that the polynomial is prime. x3+2x2−9x−18

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Group the terms of the polynomial into two pairs: \( (x^3 + 2x^2) \) and \( (-9x - 18) \). This is called factoring by grouping.
Factor out the greatest common factor (GCF) from each group. From \( x^3 + 2x^2 \), the GCF is \( x^2 \), so it becomes \( x^2(x + 2) \). From \( -9x - 18 \), the GCF is \( -9 \), so it becomes \( -9(x + 2) \).
Notice that both groups now contain the common factor \( (x + 2) \). Factor \( (x + 2) \) out of the entire expression, resulting in \( (x + 2)(x^2 - 9) \).
Observe that \( x^2 - 9 \) is a difference of squares. Recall the formula for factoring a difference of squares: \( a^2 - b^2 = (a - b)(a + b) \). Here, \( x^2 - 9 \) can be factored as \( (x - 3)(x + 3) \).
Combine all the factors to write the completely factored form of the polynomial: \( (x + 2)(x - 3)(x + 3) \).

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