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Ch. 4 - Inverse, Exponential, and Logarithmic Functions
Lial - College Algebra 13th Edition
Lial13th EditionCollege AlgebraISBN: 9780136881063당신이 사용하는 게 아니라요?교과서 변경
5장, 문제 95

Solve each equation. See Examples 4–6. 1/27 = x-3

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Start with the given equation: \(\frac{1}{27} = x^{-3}\).
Recall that a negative exponent means the reciprocal, so rewrite \(x^{-3}\) as \(\frac{1}{x^3}\), giving \(\frac{1}{27} = \frac{1}{x^3}\).
Since the fractions are equal and both have numerator 1, set the denominators equal: \(27 = x^3\).
To solve for \(x\), take the cube root of both sides: \(x = \sqrt[3]{27}\).
Simplify the cube root to find the value of \(x\).

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Negative Exponents

A negative exponent indicates the reciprocal of the base raised to the corresponding positive exponent. For example, x^(-n) equals 1 divided by x^n. Understanding this allows rewriting expressions like x^-3 as 1/x^3.
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가이드 코스
6:37
Zero and Negative Rules

Properties of Exponents

Exponent rules, such as a^(m) * a^(n) = a^(m+n) and (a^m)^n = a^(m*n), help simplify and solve equations involving powers. Applying these properties enables manipulation of expressions to isolate variables.
추천 영상:
가이드 코스
04:06
Rational Exponents

Solving Exponential Equations

Solving equations with variables in exponents often involves rewriting both sides with the same base or using logarithms. In this problem, expressing both sides as powers of 3 allows equating exponents to find x.
추천 영상:
5:47
Solving Exponential Equations Using Logs