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Multiple Choice
Given the equilibrium CO(g) + H2O(g) ⇌ CO2(g) + H2(g) with an equilibrium constant (Keq) of 302 at 600K, what is the equilibrium constant for the reverse reaction CO2(g) + H2(g) ⇌ CO(g) + H2O(g) at the same temperature?
A
0.00331
B
0.003
C
302
D
1.0
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1
Understand that the equilibrium constant (Keq) for a reaction is a measure of the ratio of the concentrations of products to reactants at equilibrium, each raised to the power of their stoichiometric coefficients.
Recognize that the equilibrium constant for the reverse reaction is the reciprocal of the equilibrium constant for the forward reaction. This is because reversing a reaction inverts the ratio of products to reactants.
Write the expression for the equilibrium constant of the forward reaction: Keq = [CO2][H2] / [CO][H2O].
For the reverse reaction, the equilibrium constant expression becomes: Keq_reverse = [CO][H2O] / [CO2][H2].
Calculate the equilibrium constant for the reverse reaction by taking the reciprocal of the given equilibrium constant for the forward reaction: Keq_reverse = 1 / 302.