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Multiple Choice
What is the equilibrium constant (K) at 305 K when the standard Gibbs free energy change (ΔG°) is +4.87 kJ/mol?
A
1.00
B
2.50
C
0.15
D
5.00
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검증된 단계별 안내
1
Understand the relationship between Gibbs free energy change (ΔG°) and the equilibrium constant (K) using the equation: ΔG° = -RT ln(K), where R is the universal gas constant (8.314 J/mol·K) and T is the temperature in Kelvin.
Convert the standard Gibbs free energy change (ΔG°) from kJ/mol to J/mol by multiplying by 1000, since 1 kJ = 1000 J.
Rearrange the equation to solve for the equilibrium constant (K): K = e^(-ΔG° / RT).
Substitute the values into the equation: ΔG° = 4870 J/mol (converted from 4.87 kJ/mol), R = 8.314 J/mol·K, and T = 305 K.
Calculate the value of K using the rearranged equation, ensuring to use the natural exponential function (e) to find the equilibrium constant.