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Multiple Choice
What is the equilibrium constant (K) at 305 K when the standard Gibbs free energy change (ΔG°) is -3.23 kJ/mol?
A
K = 1.45
B
K = 5.67
C
K = 2.34
D
K = 0.89
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검증된 단계별 안내
1
Start by understanding the relationship between the standard Gibbs free energy change (ΔG°) and the equilibrium constant (K). This relationship is given by the equation: , where R is the universal gas constant and T is the temperature in Kelvin.
Identify the values given in the problem: ΔG° = -3.23 kJ/mol, T = 305 K, and R = 8.314 J/(mol·K). Note that ΔG° is given in kJ/mol, so it should be converted to J/mol by multiplying by 1000, resulting in ΔG° = -3230 J/mol.
Rearrange the equation to solve for K: . Substitute the values into the equation: .
Calculate the value of using the values substituted into the equation. This will give you the natural logarithm of the equilibrium constant.
Finally, solve for K by taking the exponential of both sides: . This will yield the equilibrium constant at 305 K.