assign-oxidation-states-to-each-atom-in-each-element-ion-orcompound-ag-ca2-bao-h

Question

Calculate the oxidation number of each atom in the following: CrO_{4}^{2−}, NO_{3}^{−}, CaO, Zn, $$H_{2}O$$, $$Sr^{2+}$$

Accepted Answer

CrO_{4}^{2−}: Cr = +6, O = −2NO_{3}^{−}: N = +5, O = -2CaO; Ca = +2, O = −2Zn: Zn = 0H_{2}O; H = +1, O = −$$2Sr^{2+}$$: Sr = +2

Answer

CrO_{4}^{2−}: Cr = +6, O = −2NO_{3}^{−}: N = +3, O = -2CaO; Ca = +1, O = −1Zn: Zn = 0H_{2}O; H = +1, O = −$$2Sr^{2+}$$: Sr = +2

Answer

CrO_{4}^{2−}: Cr = +6, O = −2NO_{3}^{−}: N = +5, O = -1CaO; Ca = +1, O = −1Zn: Zn = 0H_{2}O; H = +1, O = −$$1Sr^{2+}$$: Sr = +2

Answer

CrO_{4}^{2−}: Cr = +4, O = −1NO_{3}^{−}: N = +5, O = -2CaO; Ca = +2, O = −2Zn: Zn = 0H_{2}O; H = +1, O = −$$1Sr^{2+}$$: Sr = +2

Calculate the oxidation number of each atom in the following: CrO42−, NO3−, CaO, Zn, H2O, Sr2+