Hypochlorous acid (HOCl) is produced when chlorine gas (Cl₂) dissolves in water:
Cl₂(g) + H₂O(l) ⇌ HOCl(aq) + HCl(aq)
The solubility of chlorine in water at 30 °C is 0.576 g/100 mL. Calculate the pH and the concentrations of all species (H₃O⁺, OH^–, HOCl, OCl^–, and Cl^–) in a saturated chlorine solution at this temperature. Assume that all chlorine reacts with water. (K_a of HOCl = 2.95×10^–8)

[H₃O⁺] = 0.0775 M

[OH^–] = 1.23×10^–13 M

[HOCl] = 0.0847 M

[OCl^–] = 2.95×10^–8 M

[Cl^–] = 0.0812 M

pH = 1.117

[H₃O⁺] = 0.0775 M

[OH^–] = 1.23×10^–13 M

[HOCl] = 0.0847 M

[OCl^–] = 2.12×10^–8 M

[Cl^–] = 0.0873 M

pH = 1.883

[H₃O⁺] = 0.0812 M

[OH^–] = 1.23×10^–13 M

[HOCl] = 0.0812 M

[OCl^–] = 2.95×10^–8 M

[Cl^–] = 0.0812 M

pH = 1.090

[H₃O⁺] = 0.0975 M

[OH^–] = 4.23×10^–13 M

[HOCl] = 0.0847 M

[OCl^–] = 2.12×10^–8 M

[Cl^–] = 0.0873 M

pH = 1.883