the-rate-constant-for-the-radioactive-decay-of-berkelium-248-248bk-and-seaborgiu-1

Question

The first-order rate constant for the radioactive decay of Berkelium-248 $$(^{248}Bk) $$and Seaborgium-260 $$(^{260}Sg) is 0.0292 hk=M-n+1$$·t-1' tabindex="0"\$$u003e^{−}$$^{1} and 0.173 msk=M-n+1·t-1' tabindex="0"\$$u003e^{−}$$^{1}, respectively. Which sample decays at a faster rate?

Accepted Answer

Seaborgium-260 has a faster decay rate

Answer

Berkelium-248 has a faster decay rate

Answer

Seaborgium-260 and Berkelium-248 have equal decay rate

The first-order rate constant for the radioactive decay of Berkelium-248 (248Bk) and Seaborgium-260 (260Sg) is 0.0292 h−1 and 0.173 ms−1, respectively. Which sample decays at a faster rate?

The first-order rate constant for the radioactive decay of Berkelium-248 (²⁴⁸Bk) and Seaborgium-260 (²⁶⁰Sg) is 0.0292 h $k = M^{- n + 1} \cdot t^{- 1}$ ¹ and 0.173 ms $k = M^{- n + 1} \cdot t^{- 1}$ ¹, respectively. Which sample decays at a faster rate?