copper-exists-in-nature-as-cu-cu-and-cu2-copper-loses-an-electron-when-it-goes-f

Question

Mercury exists in nature as Hg, $$Hg^{+}$$, and $$Hg^{2+}. $$Mercury loses an electron when it goes from $$Hg^{+} to$$ $$Hg^{2+}. $$Give the n and l quantum numbers of the electron lost from this transition.

Accepted Answer

n = 6, l = 0

Answer

n = 6, l = 1

Answer

n = 5, l = 2

Answer

n = 4, l = 3

Mercury exists in nature as Hg, Hg+, and Hg2+. Mercury loses an electron when it goes from Hg+ to Hg2+. Give the n and l quantum numbers of the electron lost from this transition.

Mercury exists in nature as Hg, Hg⁺, and Hg²⁺. Mercury loses an electron when it goes from Hg⁺ to Hg²⁺. Give the n and l quantum numbers of the electron lost from this transition.