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Ch.21 - Nuclear Chemistry
Brown - Chemistry: The Central Science 14th Edition
Brown14th EditionChemistry: The Central ScienceISBN: 9780134414232당신이 사용하는 게 아니라요?교과서 변경
21장, 문제 13b

Write balanced nuclear equations for the following processes: (b) selenium-72 undergoes electron capture.

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1
Identify the process: Electron capture involves an inner orbital electron being captured by the nucleus, which combines with a proton to form a neutron.
Write the initial isotope: Selenium-72 is represented as \( ^{72}_{34}\text{Se} \).
Determine the change in the nucleus: During electron capture, a proton is converted into a neutron, so the atomic number decreases by 1, but the mass number remains the same.
Write the resulting isotope: The new element will have an atomic number of 33 (since 34 - 1 = 33), which is arsenic (As), so the resulting isotope is \( ^{72}_{33}\text{As} \).
Write the balanced nuclear equation: \( ^{72}_{34}\text{Se} + e^- \rightarrow ^{72}_{33}\text{As} \), where \( e^- \) represents the captured electron.

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Electron Capture

Electron capture is a type of radioactive decay in which an atomic nucleus captures an inner-shell electron, typically from the K-shell. This process results in the conversion of a proton into a neutron, leading to a decrease in the atomic number of the element while the mass number remains unchanged. It is a common decay mode for proton-rich isotopes, allowing them to achieve a more stable configuration.
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01:26
Electron Capture

Nuclear Equations

Nuclear equations represent the transformation of one element into another during nuclear reactions, including decay processes. They are written to show the initial and final states of the nucleus, including the emission or absorption of particles. In these equations, the atomic number and mass number must be balanced, ensuring that the total number of protons and neutrons remains constant before and after the reaction.
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02:06
Nuclear Binding Energy

Selenium-72

Selenium-72 is a radioactive isotope of selenium with 34 protons and 38 neutrons, giving it a mass number of 72. It undergoes various decay processes, including electron capture, to achieve stability. Understanding its nuclear properties and behavior is essential for writing accurate nuclear equations, as it provides the necessary information about the starting material in the reaction.
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01:04
Hydrogen Compounds Example