The equilibrium constant constant ๐พ๐ for C(๐ ) + CO2(๐) โ 2 CO(๐) is 1.9 at 1000 K and 0.133 at 298 K. (a) If excess C is allowed to react with 25.0 g of CO2 in a 3.00-L vessel at 1000 K, how many grams of CO are produced? (b) If excess C is allowed to react with 25.0 g of CO2 in a 3.00-L vessel at 1000 K, how many grams of C are consumed?
At 700 K, the equilibrium constant for the reaction CCl4(๐) โ C(๐ ) + 2 Cl2(๐) is ๐พ๐ = 0.76. A flask is charged with 2.00 atm of CCl4, which then reaches equilibrium at 700 K. (a) What fraction of the CCl4 is converted into C and Cl2?
๊ฒ์ฆ๋ ๋จ๊ณ๋ณ ์๋ด
๋น์ทํ ๋ฌธ์ ์ ๋ํ ๊ฒ์ฆ๋ ์์ ๋ต๋ณ:
์ฃผ์ ๊ฐ๋
Equilibrium Constant (Kp)
Le Chatelier's Principle
Stoichiometry of the Reaction
Consider the hypothetical reaction A(๐) + 2 B(๐) โ 2 C(๐), for which ๐พ๐ = 0.25 at a certain temperature. A 1.00-L reaction vessel is loaded with 1.00 mol of compound C, which is allowed to reach equilibrium. Let the variable x represent the number of mol/L of compound A present at equilibrium.
(d) The equation from part (c) is a cubic equation (one that has the form ax3 + bx2 + cx + d = 0). In general, cubic equations cannot be solved in closed form. However, you can estimate the solution by plotting the cubic equation in the allowed range of x that you specified in part (b). The point at which the cubic equation crosses the x-axis is the solution.
(e) From the plot in part (d), estimate the equilibrium concentrations of A, B, and C. (Hint: You can check the accuracy of your answer by substituting these concentrations into the equilibrium expression.)
At 700 K, the equilibrium constant for the reaction CCl4(๐) โ C(๐ ) + 2 Cl2(๐) is ๐พ๐ = 0.76. A flask is charged with 2.00 atm of CCl4, which then reaches equilibrium at 700 K. (b) What are the partial pressures of CCl4 and Cl2 at equilibrium?
