A voltaic cell utilizes the following reaction: (b) What is the emf for this cell when 3Fe3+4 = 3.50 M, PH2= 0.95 atm, 3Fe2+4 = 0.0010 M, and the pH in both half-cells is 4.00?

검증된 단계별 안내

Identify the half-reactions and write the overall balanced equation for the cell. For a voltaic cell involving iron and hydrogen, the anode (oxidation) reaction might be Fe2+ -> Fe3+ + e-, and the cathode (reduction) reaction might be 2H+ + 2e- -> H2.

Use the Nernst equation to calculate the emf of the cell. The Nernst equation is E = E^0 - (RT/nF) * lnQ, where E^0 is the standard cell potential, R is the gas constant, T is the temperature in Kelvin, n is the number of moles of electrons transferred, F is the Faraday constant, and Q is the reaction quotient.

Calculate the reaction quotient, Q, for the cell reaction. Q is given by the expression Q = ([Fe3+]^3 * PH2) / ([Fe2+]^3 * [H+]^4). Use the given concentrations and pressures, and remember to convert pH to [H+] using [H+] = 10^(-pH).

Substitute the values of E^0, R, T, n, F, and Q into the Nernst equation. Use standard conditions and values for E^0, R, T, and F. For this reaction at 25°C (298 K), R = 8.314 J/(mol*K) and F = 96485 C/mol.

Solve the Nernst equation to find the emf, E, of the cell. This will give you the potential difference driving the cell under the specified non-standard conditions.

비슷한 문제에 대한 검증된 영상 답변:

이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.

영상 길이:

12m

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Electrochemical Cells

Electrochemical cells, such as voltaic cells, convert chemical energy into electrical energy through redox reactions. In these cells, oxidation occurs at the anode and reduction at the cathode, allowing for the flow of electrons through an external circuit. Understanding the components and functioning of these cells is essential for calculating their electromotive force (emf).

Nernst Equation

The Nernst equation relates the emf of an electrochemical cell to the concentrations of the reactants and products involved in the redox reaction. It accounts for non-standard conditions, allowing for the calculation of the cell potential based on the concentrations of ions and gases. This equation is crucial for determining the emf in the given scenario with varying concentrations and pressures.

pH and Its Effect on Cell Potential

pH is a measure of the hydrogen ion concentration in a solution, which can significantly influence the behavior of electrochemical reactions. In the context of a voltaic cell, changes in pH can affect the concentration of H+ ions, thereby impacting the equilibrium and the overall cell potential. Understanding how pH interacts with the redox reactions is vital for accurate emf calculations.