(a) Which region of the periodic table shown here contains elements that are easiest to oxidize? (b) Which region contains the least readily oxidized elements?
Ch.4 - Reactions in Aqueous Solution
4장, 문제 48d
Determine the oxidation number of sulfur in each of the following substances: (d) hydrogen sulfide, H2S
검증된 단계별 안내1
Identify the oxidation number of hydrogen (H), which is typically +1.
Let the oxidation number of sulfur (S) be x.
Write the equation for the sum of oxidation numbers in the compound: 2(+1) + x = 0, since the compound is neutral.
Simplify the equation: 2 + x = 0.
Solve for x to find the oxidation number of sulfur.

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1m주요 개념
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Oxidation Number
The oxidation number, or oxidation state, is a theoretical charge assigned to an atom in a compound based on the assumption that electrons are completely transferred. It helps in understanding the electron distribution in molecules and is crucial for identifying redox reactions. Oxidation numbers can be positive, negative, or zero, depending on the atom's electron gain or loss.
추천 영상:
가이드 코스
Oxidation Numbers
Rules for Assigning Oxidation Numbers
There are specific rules for assigning oxidation numbers, such as the fact that the oxidation number of an element in its standard state is zero, and for monoatomic ions, it equals the charge of the ion. In compounds, hydrogen typically has an oxidation number of +1, while oxygen usually has -2. These rules guide the determination of oxidation states in various compounds.
추천 영상:
가이드 코스
Oxidation Number Rules
Hydrogen Sulfide (H2S)
Hydrogen sulfide (H2S) is a simple binary compound consisting of hydrogen and sulfur. In H2S, each hydrogen atom has an oxidation number of +1, leading to a total of +2 from the two hydrogens. To balance this, the sulfur must have an oxidation number of -2, making it essential to apply the rules of oxidation states to determine sulfur's charge in this compound.
추천 영상:
가이드 코스
Hydrogenation Reactions
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