Skip to main content
Ch.5 - Thermochemistry
Brown - Chemistry: The Central Science 15th Edition
Brown15th EditionChemistry: The Central ScienceISBN: 9780137542970당신이 사용하는 게 아니라요?교과서 변경
5장, 문제 57a

A 2.200-g sample of quinone (C6H4O2) is burned in a bomb calorimeter whose total heat capacity is 7.854 kJ/°C. The temperature of the calorimeter increases from 23.44 to 30.57 °C. (a) What is the heat of combustion per gram of quinone?

검증된 단계별 안내
1
Calculate the temperature change (\( \Delta T \)) of the calorimeter by subtracting the initial temperature from the final temperature: \( \Delta T = 30.57 \, ^\circ\text{C} - 23.44 \, ^\circ\text{C} \).
Use the formula for heat absorbed by the calorimeter: \( q = C_{\text{cal}} \times \Delta T \), where \( C_{\text{cal}} \) is the heat capacity of the calorimeter (7.854 kJ/°C).
Substitute the values into the formula to find the total heat absorbed by the calorimeter: \( q = 7.854 \, \text{kJ/°C} \times \Delta T \).
Determine the heat of combustion per gram of quinone by dividing the total heat absorbed by the mass of the quinone sample: \( \text{Heat of combustion per gram} = \frac{q}{\text{mass of quinone}} \).
Substitute the mass of the quinone sample (2.200 g) into the equation to find the heat of combustion per gram.

비슷한 문제에 대한 검증된 영상 답변:

이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
4m

주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Heat Capacity

Heat capacity is the amount of heat energy required to change the temperature of a substance by one degree Celsius. In calorimetry, the heat capacity of the calorimeter is crucial for determining the total heat absorbed during a reaction. It allows us to calculate the heat released by the combustion of a sample by multiplying the heat capacity by the change in temperature.
추천 영상:

Calorimetry

Calorimetry is the science of measuring the heat of chemical reactions or physical changes. In a bomb calorimeter, the heat released from a combustion reaction is measured by observing the temperature change in the calorimeter. This technique is essential for determining the energy content of fuels and other substances, such as quinone in this case.
추천 영상:
가이드 코스
00:50
Constant-Volume Calorimetry

Heat of Combustion

The heat of combustion is the amount of energy released when a substance is completely burned in oxygen. It is typically expressed in joules or kilojoules per gram. To find the heat of combustion per gram of quinone, the total heat released during the combustion process is divided by the mass of the sample, providing a measure of its energy content.
추천 영상:
가이드 코스
02:24
Combustion Apparatus
관련 실천
교과서 질문

(b) Is this process endothermic or exothermic?

487
views
교과서 질문

A 1.800-g sample of phenol (C6H5OH) was burned in a bomb calorimeter whose total heat capacity is 11.66 kJ/°C. The temperature of the calorimeter plus contents increased from 21.36 to 26.37 °C. b. What is the heat of combustion per gram of phenol?

2
views
교과서 질문

When a 5.10-g sample of solid sodium hydroxide dissolves in 100.0 g of water in a coffee-cup calorimeter (Figure 5.18), the temperature rises from 20.5 to 33.2 °C. b. Using your result from part (a), calculate ΔH (in kJ/mol NaOH) for the solution process. Assume that the specific heat of the solution is the same as that of pure water.

2
views
교과서 질문

When a 5.10-g sample of solid sodium hydroxide dissolves in 100.0 g of water in a coffee-cup calorimeter (Figure 5.18), the temperature rises from 20.5 to 33.2 °C. a. Calculate the quantity of heat (in kJ) released in the reaction.

3
views
교과서 질문

A 2.200-g sample of quinone (C6H4O2) is burned in a bomb calorimeter whose total heat capacity is 7.854 kJ/°C. The temperature of the calorimeter increases from 23.44 to 30.57 °C. b. What is the heat of combustion per mole of quinone?

3
views
교과서 질문

A 1.800-g sample of phenol (C6H5OH) was burned in a bomb calorimeter whose total heat capacity is 11.66 kJ/°C. The temperature of the calorimeter plus contents increased from 21.36 to 26.37 °C. a. Write a balanced chemical equation for the bomb calorimeter reaction.

5
views