Determine the pH of each solution. a. 0.048 M HI b. 0.0895 M HClO 4 c. a solution that is 0.045 M in HClO 4 and 0.048 M in HCl d. a solution that is 1.09% HCl by mass (assume a density of 1.01 g/mL for the solution)

Step 1: Understand the nature of the acids involved. HI and HClO_{4} are strong acids, meaning they dissociate completely in water. This means the concentration of $$H^{+}$$ ions in the solution is equal to the concentration of the acid.. Step 2: Calculate the pH for each solution using the formula: $$ \text{pH} = -\log[\text{H}^+] . $$For part (a), use the concentration of HI, which is 0.048 M.. Step 3: For part (b), use the concentration of HClO_{4}, which is 0.0895 M, to find the pH using the same formula.. Step 4: For part (c), since both HClO_{4} and HCl are strong acids, add their concentrations to find the total [$$H^{+}$$] and then calculate the pH.. Step 5: For part (d), convert the percentage concentration of HCl to molarity. Use the formula: $$ \text{Molarity} = \frac{\text{mass percent} \times \text{density} \times 10}{\text{molar mass of HCl}} . $$Then, calculate the pH using the molarity obtained.

Determine the pH of each solution. a. 0.048 M HI b. 0.0895 M HClO4 c. a solution that is 0.045 M in HClO4 and 0.048 M in HCl d. a solution that is 1.09% HCl by mass (assume a density of 1.01 g/mL for the solution)

Step 1: Understand the nature of the acids involved. HI and HClO_{4} are strong acids, meaning they dissociate completely in water. This means the concentration of $$H^{+}$$ ions in the solution is equal to the concentration of the acid. Step 2: Calculate the pH for each solution using the formula: $$ \text{pH} = -\log[\text{H}^+] . $$For part (a), use the concentration of HI, which is 0.048 M. Step 3: For part (b), use the concentration of HClO_{4}, which is 0.0895 M, to find the pH using the same formula. Step 4: For part (c), since both HClO_{4} and HCl are strong acids, add their concentrations to find the total [$$H^{+}$$] and then calculate the pH. Step 5: For part (d), convert the percentage concentration of HCl to molarity. Use the formula: $$ \text{Molarity} = \frac{\text{mass percent} \times \text{density} \times 10}{\text{molar mass of HCl}} . $$Then, calculate the pH using the molarity obtained.

Ch.16 - Acids and Bases

Tro - Chemistry: A Molecular Approach 4th Edition

Tro4th EditionChemistry: A Molecular ApproachISBN: 9780134112831당신이 사용하는 게 아니라요?교과서 변경

모든 교과서

Tro 4th Edition

Ch.16 - Acids and Bases

문제 58

16장, 문제 58

Determine the pH of each solution. a. 0.048 M HI b. 0.0895 M HClO₄ c. a solution that is 0.045 M in HClO₄ and 0.048 M in HCl d. a solution that is 1.09% HCl by mass (assume a density of 1.01 g/mL for the solution)

검증된 단계별 안내

Step 1: Understand the nature of the acids involved. HI and HClO₄ are strong acids, meaning they dissociate completely in water. This means the concentration of H⁺ ions in the solution is equal to the concentration of the acid.

Step 2: Calculate the pH for each solution using the formula: $ \text{pH} = -\log[\text{H}^+] $. For part (a), use the concentration of HI, which is 0.048 M.

Step 3: For part (b), use the concentration of HClO₄, which is 0.0895 M, to find the pH using the same formula.

Step 4: For part (c), since both HClO₄ and HCl are strong acids, add their concentrations to find the total [H⁺] and then calculate the pH.

Step 5: For part (d), convert the percentage concentration of HCl to molarity. Use the formula: $ \text{Molarity} = \frac{\text{mass percent} \times \text{density} \times 10}{\text{molar mass of HCl}} $. Then, calculate the pH using the molarity obtained.

비슷한 문제에 대한 검증된 영상 답변:

이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.

영상 길이:

도움이 되었나요?

주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Strong Acids and pH Calculation

Strong acids, such as HI and HClO4, completely dissociate in water, meaning that the concentration of hydrogen ions (H+) in solution is equal to the concentration of the acid. The pH of a solution is calculated using the formula pH = -log[H+]. For example, a 0.048 M HI solution will have a pH of -log(0.048), which can be computed directly.

Mixed Acid Solutions

When dealing with mixed acid solutions, such as the one containing both HClO4 and HCl, the total concentration of H+ ions is the sum of the contributions from each acid. Since both are strong acids, their concentrations can be added directly to find the total H+ concentration, which is then used to calculate the overall pH of the solution.

Mass Percent Concentration to Molarity Conversion

To determine the pH of a solution given in mass percent, such as 1.09% HCl, it is necessary to convert this to molarity. This involves calculating the mass of HCl in a given volume of solution, using the density to find the volume, and then converting the mass to moles using the molar mass of HCl. The resulting molarity can then be used to find the pH.