Write the electron configuration for oxygen. Then write the Le...

Question

Write the electron configuration for oxygen. Then write the Lewis symbol for oxygen and show which electrons from the electron configuration are included in the Lewis symbol.

Accepted Answer

First, determine the electron configuration of oxygen. Oxygen has an atomic number of 8, which means it has 8 electrons. The electron configuration is filled by adding electrons to the lowest energy orbitals first, following the Aufbau principle, Hund's rule, and the Pauli exclusion principle. The configuration starts with the 1s orbital, then the 2s orbital, and finally the 2p orbitals.. Write the electron configuration for oxygen. The first two electrons will fill the 1s orbital, the next two will fill the 2s orbital, and the remaining four electrons will partially fill the 2p orbital. The electron configuration of oxygen is therefore: $$1s^2$$ $$2s^2$$ $$2p^4.. $$Next, write the Lewis symbol for oxygen. The Lewis symbol represents the valence electrons (electrons in the outermost shell) as dots around the element's symbol. For oxygen, the valence electrons are those in the 2s and 2p orbitals.. Place the valence electrons around the symbol 'O' for oxygen. According to the Lewis structure rules, distribute the electrons to minimize repulsion. Start by placing one electron on each of the four sides (top, bottom, left, right) before pairing them. This results in two lone pairs and two single electrons, which are represented as dots around the 'O'.. Identify which electrons from the electron configuration are shown in the Lewis symbol. The electrons in the Lewis symbol for oxygen are the six valence electrons from the 2s and 2p orbitals, specifically the $$2s^2$$ $$2p^4$$ electrons.

Write the electron configuration for oxygen. Then write the Lewis symbol for oxygen and show which electrons from the electron configuration are included in the Lewis symbol.

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주요 개념

Electron Configuration

Lewis Symbols

Valence Electrons