What is the minimum amount of 6.0 M H₂SO₄ necessary to produce 25.0 g of H₂(g) according to the reaction between aluminum and sulfuric acid? 2 Al(s) + 3 H₂SO₄(aq) → Al₂(SO₄)₃(aq) + 3 H₂(g)

검증된 단계별 안내

Determine the molar mass of H_2 by adding the atomic masses of hydrogen atoms.

Calculate the moles of H_2 produced using the formula: moles = mass / molar mass.

Use the stoichiometry of the balanced chemical equation to find the moles of H_2SO_4 needed. According to the equation, 3 moles of H_2SO_4 produce 3 moles of H_2.

Calculate the volume of 6.0 M H_2SO_4 solution required using the formula: volume = moles / molarity.

Ensure the units are consistent and convert the volume to the desired unit if necessary.

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Stoichiometry

Stoichiometry is the calculation of reactants and products in chemical reactions based on the balanced chemical equation. It allows us to determine the proportions of substances involved in a reaction, which is essential for converting between grams and moles. In this case, stoichiometry will help us find out how much sulfuric acid is needed to produce a specific mass of hydrogen gas.

Molarity

Molarity is a measure of concentration defined as the number of moles of solute per liter of solution. It is crucial for understanding how much of a concentrated solution, like 6.0 M H2SO4, is required to achieve a desired amount of product. By knowing the molarity, we can calculate the volume of sulfuric acid needed to react with aluminum to produce the specified amount of hydrogen gas.

Limiting Reactant

The limiting reactant is the substance that is completely consumed first in a chemical reaction, thus determining the maximum amount of product that can be formed. Identifying the limiting reactant is essential for accurately calculating the quantities of reactants needed. In this scenario, we need to ensure that we have enough sulfuric acid to react with aluminum to produce the desired amount of hydrogen gas.

What is the minimum amount of 6.0 M H2SO4 necessary to produce 25.0 g of H2(g) according to the reaction between aluminum and sulfuric acid? 2 Al(s) + 3 H2SO4(aq) → Al2(SO4)3(aq) + 3 H2(g)