Consider the following reaction: 2 C6H6 (l) + 15 O2 (g) → 12 CO2 (g) + 6 H2O (g) ∆Hº = – 6278 kJ What volume of benzene (C6H6, d = 0.880 g/mL, molar mass = 78.11 g/mol) is necessary to evolve 5.19 x 109 kJ of heat?
A
1.47 x 108 mL
B
5.19 x 109 mL
C
4.37 x 107 mL
D
9.51 x 109 mL
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Start by understanding the given reaction: 2 C6H6 (l) + 15 O2 (g) → 12 CO2 (g) + 6 H2O (g) with ∆Hº = – 6278 kJ. This indicates that 6278 kJ of heat is released when 2 moles of benzene react.
Calculate the number of moles of benzene required to evolve 5.19 x 10^9 kJ of heat. Use the relationship: moles of C6H6 = (desired heat / heat per 2 moles of C6H6).
Convert the moles of benzene to grams using its molar mass (78.11 g/mol). Use the formula: mass (g) = moles x molar mass.
Convert the mass of benzene to volume using its density (0.880 g/mL). Use the formula: volume (mL) = mass (g) / density (g/mL).
Review the calculated volume and compare it with the given options to identify the correct answer.