A cylinder with a movable piston contains 0.615 moles of gas and has a volume of 295 mL. What will its volume be if 0.103 moles of gas escaped?
A
0.176 L
B
0.217 L
C
0.246 L
D
0.361 L
E
1.28 L
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1
Identify the initial conditions: The cylinder contains 0.615 moles of gas with a volume of 295 mL.
Determine the final amount of gas: Subtract the moles of gas that escaped (0.103 moles) from the initial moles (0.615 moles) to find the remaining moles of gas.
Use the ideal gas law concept: Since the pressure and temperature are constant, apply the relationship \( V_1 / n_1 = V_2 / n_2 \), where \( V \) is volume and \( n \) is the number of moles.
Substitute the known values into the equation: \( V_1 = 295 \) mL, \( n_1 = 0.615 \) moles, and \( n_2 \) is the remaining moles after the gas escaped.
Solve for \( V_2 \): Rearrange the equation to find \( V_2 = V_1 \times (n_2 / n_1) \) and calculate the new volume in mL, then convert it to liters if necessary.