교과서 질문
Complete the following equations. (Hint: Remember that a nitrogen with three groups bound to it has a lone pair and one with four does not)
a.
789
views
17. Amines
Amine Reactions
Multiple Choice
Determine the ammonium ion formed in the following reaction between diethylamine and hydrobromic acid.
A
B
C
D
검증된 단계별 안내1
Identify the reactants: Diethylamine (C2H5)2NH and hydrobromic acid (HBr).
Recognize that diethylamine is a secondary amine with a lone pair of electrons on the nitrogen atom, making it a base.
Understand that hydrobromic acid (HBr) is a strong acid that can donate a proton (H+).
In the reaction, the lone pair on the nitrogen atom of diethylamine will accept a proton from HBr, forming an ammonium ion.
The resulting ammonium ion will have the formula (C2H5)2NH2+, where the nitrogen atom now has four bonds and a positive charge.
Related Videos
Related Practice
