separate-this-redox-reaction-into-its-balanced-component-half-reactions-cl2-2na--1

Question

The following is a redox reaction between potassium and bromine to form potassium bromide:2 K + Br_{2} → 2 KBrSeparate this redox reaction into its component half-reaction.

Accepted Answer

Oxidation Half Reaction: 2 K → 2 $$K^{+} + 2$$ $$e^{-}$$Reduction Half Reaction: Br_{2} + 2 $$e^{-}$$ → 2 $$Br^{-}$$

Answer

Oxidation Half Reaction: K → $$K^{+}$$ + $$e^{-}$$Reduction Half Reaction: Br_{2} + 2 $$e^{-}$$ → 2 $$Br^{-}$$

Answer

Oxidation Half Reaction: 2 K → 2 $$K^{+} + 2$$ $$e^{-}$$Reduction Half Reaction: Br + $$e^{-}$$ → $$Br^{-}$$

Answer

Oxidation Half Reaction: K → $$K^{+}$$ + $$e^{-}$$Reduction Half Reaction: Br + $$e^{-}$$ → $$Br^{-}$$

The following is a redox reaction between potassium and bromine to form potassium bromide:2 K + Br2 → 2 KBrSeparate this redox reaction into its component half-reaction.

The following is a redox reaction between potassium and bromine to form potassium bromide:
2 K + Br₂ → 2 KBr
Separate this redox reaction into its component half-reaction.