the-boiling-point-of-the-solution-obtained-by-dissolving-x-mol-of-x-in-x-kg-of-x

Question

The boiling point of the solution obtained by dissolving 1.00 mol of acetic acid ($$CH_{3}$$COOH) in 1.00 kg of water ($$H_{2}O) is 100.7$$°C. Determine whether X is a weak or strong electrolyte. Explain.

Accepted Answer

Acetic acid is a weak electrolyte since it does not dissociate completely in water.

Answer

Acetic acid is a strong electrolyte since it dissociates completely in water.

Answer

Acetic acid is a weak electrolyte since it dissociates completely in water.

Answer

Acetic acid is a strong electrolyte since it does not dissociate completely in water.

The boiling point of the solution obtained by dissolving 1.00 mol of acetic acid (CH3COOH) in 1.00 kg of water (H2O) is 100.7°C. Determine whether X is a weak or strong electrolyte. Explain.

The boiling point of the solution obtained by dissolving 1.00 mol of acetic acid (CH₃COOH) in 1.00 kg of water (H₂O) is 100.7°C. Determine whether X is a weak or strong electrolyte. Explain.