Which of the following statements correctly explains why the equation: $a(b-c)=ab-ac$ is written in terms of treating subtraction as an addition of a negative?

Because only the first term inside parentheses is multiplied and the second term remains unchanged, so $a(b-c)=ab-c$

Because subtraction implies division by $-1$ before distribution, leading to $a(b-c)=\frac{ab}{-1}-\frac{ac}{-1}$

Because subtraction inside parentheses changes the sign of the outside multiplier to positive, so $a(b-c)=ab+ac$

Because $b-c$ is the same as $b+(-c)$, and distributing gives $ab+a(-c)=ab-ac$