Intermediate Algebra
5x2y35x^2 y^3
5x2y3\(\displaystyle\]\frac{5x^2}{y^3}\)
5x2y3\(\displaystyle\]\frac{5}{x^2y^3}\)
x−2y−35\(\displaystyle\]\frac{x^{-2}\)y^{-3}}{5}