c2d64e79-mon-coefficient-of-the-squared-terms-what-is-the-standard-form-center-a

Question

Convert 2x2+2y2+8x−12y+6=$$02x^2$+2y^2+8x-12y+6=0 $$into standard form. What is the standard form, center, and radius of this circle?

Accepted Answer

(x+2)2+(y−3)2=$$10(x+2)^2$+(y-3)^2=10$$, with center (−2,3)\left(-2,3\right) and radius 10\sqrt{10}

Answer

(x−2)2+(y+3)2=$$10(x-2)^2$+(y+3)^2=10$$, with center (2,−3)(2, −3) and radius 10\sqrt{10}

Answer

(x+2)2+(y−3)2=$$5(x+2)^2$+(y-3)^2=5$$, with center (−2,3)\left(-2,3\right) and radius 5\sqrt5

Answer

(x+2)2+(y−3)2=$$5(x+2)^2$+(y-3)^2=5$$, with center (−2,3)\left(-2,3\right) and radius 10\sqrt{10}

Convert 2x2+2y2+8x−12y+6=02x^2+2y^2+8x-12y+6=0 into standard form. What is the standard form, center, and radius of this circle?