Simplify and state excluded values: $\frac{x^2-5x+6}{x^2-4}$

$\frac{x-3}{x+2}$, $x\ne -2$

$\frac{x-3}{x+2}$, for all $x$

$x-3$, $x\ne -2$

$\frac{x-3}{x+2}$ , $x\ne 2$ and $x\ne -2$