Which statement correctly describes the behavior of $n$^th roots for integers $n\ge 2$?

If $n$ is odd, every real radicand has exactly one real $n$^th root; if $n$ is even, a positive radicand has two real roots ($\pm$), and a negative radicand has no real roots

Every radical expression yields two real roots, regardless of the index, unless the radicand is zero

Only square roots depend on parity; higher-order roots like $\sqrt[4]{x}$ or $\sqrt[5]{x}$ always have exactly one real root

If $n$ is even, there is always exactly one real root; if $n$ is odd, there are always two real roots