Intermediate Algebra
x=116y2\(\displaystyle\) x = \(\frac{1}{16}\)y^2
y=116x2\(\displaystyle\) y = \(\frac{1}{16}\)x^2
x=14y2\(\displaystyle\]\displaystyle\) x=\(\frac{1}{4}\)y^2
x=16y2x = 16y^2