Consider a real-world situation where a dietitian is dealing with a system of equations where the calories $c$ and the grams of protein $p$ are related to each other and are written as: $p=0.1c-5$ and $3p+2c=480$. Solve for the calorie target value $c$ by using the substitution method.

Approximately 214 calories, as you should subtract 1 for safety in diet planning after solving algebraically

Approximately 215.217 calories (exactly 4950/23), found by substituting for p and solving 2.3c = 495

Exactly 215 calories, since calories are integers, so you round down after solving the algebraic equation to get the nearest whole-number target

There is no valid calorie value, since substitution produces a contradictory equation, so c cannot be computed algebraically from the given relations