뒤로Step-by-Step Guidance for Solving Linear Inequalities and Expressing Solutions in Interval Notation
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Q1. Solve the following inequality. Write the solution set using interval notation:
19 + 7x \geq 2x - 5
Background
Topic: Linear Inequalities
This question tests your ability to solve a linear inequality and express the solution set using interval notation.
Key Terms and Formulas:
Linear Inequality: An inequality involving a linear expression, such as $ax + b \leq c$.
Interval Notation: A way to describe the set of solutions using parentheses and/or brackets.
Step-by-Step Guidance
Start by isolating the variable $x$ on one side. Subtract $2x$ from both sides:
$19 + 7x - 2x \geq -5$
Simplify the left side by combining like terms:
$19 + 5x \geq -5$
Subtract $19$ from both sides to further isolate $x$:
$5x \geq -5 - 19$
Simplify the right side and prepare to solve for $x$ by dividing both sides by $5$.
Try solving on your own before revealing the answer!
Final Answer:
$x \geq -\frac{24}{5}$
In interval notation, the solution set is $\left[ -\frac{24}{5}, \infty \right)$.
We isolated $x$ and expressed the solution using the correct interval notation for a "greater than or equal to" inequality.
Q2. Solve the following inequality. Write the solution set in interval notation:
7(x - 3) \leq 2(4x - 1)
Background
Topic: Linear Inequalities with Distribution
This question tests your ability to solve inequalities that require distributing and combining like terms before isolating the variable.
Key Terms and Formulas:
Distributive Property: $a(b + c) = ab + ac$
Interval Notation: Used to express the solution set.
Step-by-Step Guidance
Apply the distributive property to both sides:
$7x - 21 \leq 8x - 2$
Get all terms involving $x$ on one side and constants on the other. Subtract $7x$ from both sides:
$-21 \leq x - 2$
Add $2$ to both sides to isolate $x$:
$-21 + 2 \leq x$
Simplify the left side and write the solution in $x \geq$ form, then express in interval notation.
Try solving on your own before revealing the answer!
Final Answer:
$x \geq -19$
In interval notation, the solution set is $[-19, \infty)$.
We used the distributive property and isolated $x$ to find the solution set.
Q3. Solve the following inequality. Write the solution set in interval notation:
-3(x - 1) < -2[5 + 8(x + 5)]
Background
Topic: Linear Inequalities with Distribution and Combining Like Terms
This question tests your ability to handle distribution, combining like terms, and solving inequalities with negative coefficients.
Key Terms and Formulas:
Distributive Property: $a(b + c) = ab + ac$
Combining Like Terms: Add or subtract terms with the same variable.
Step-by-Step Guidance
Distribute $-3$ on the left and $-2$ on the right:
$-3x + 3 < -2 \times 5 - 2 \times 8(x + 5)$
Simplify the right side by distributing $-2$ to both $5$ and $8(x + 5)$, then expand $8(x + 5)$.
Combine like terms on both sides to get all $x$ terms on one side and constants on the other.
Isolate $x$ and prepare to divide by the coefficient of $x$ (remember to reverse the inequality if dividing by a negative).
Try solving on your own before revealing the answer!
Final Answer:
$x > -\frac{8}{13}$
In interval notation, the solution set is $\left( -\frac{8}{13}, \infty \right)$.
We distributed, combined like terms, and solved for $x$, remembering to reverse the inequality when dividing by a negative.
Q4. Solve.
\frac{1}{2} + \frac{3}{7} \geq \frac{x}{14}
Background
Topic: Linear Inequalities with Fractions
This question tests your ability to solve inequalities involving fractions and to express the solution in terms of $x$.
Key Terms and Formulas:
Common Denominator: To add or compare fractions, rewrite them with a common denominator.
Solving for $x$: Isolate $x$ on one side of the inequality.
Step-by-Step Guidance
Find a common denominator for the fractions on the left side.
Add the fractions together to get a single fraction on the left.
Set up the inequality so that you have a single fraction on each side: $\frac{a}{b} \geq \frac{x}{14}$.
Multiply both sides by $14$ to clear the denominators and solve for $x$.
Try solving on your own before revealing the answer!
Final Answer:
$x \leq 13$
The solution set is $(-\infty, 13]$ in interval notation.
We combined the fractions, isolated $x$, and expressed the solution using interval notation.
Q5. Solve the following inequality. Write the solution set using interval notation:
3(x - 6) + 3x - 10 \geq 2(x - 8) + 10x
Background
Topic: Linear Inequalities with Distribution and Combining Like Terms
This question tests your ability to distribute, combine like terms, and solve for $x$ in a linear inequality.
Key Terms and Formulas:
Distributive Property: $a(b + c) = ab + ac$
Combining Like Terms: Add or subtract terms with the same variable.
Step-by-Step Guidance
Distribute $3$ on the left and $2$ on the right:
$3x - 18 + 3x - 10 \geq 2x - 16 + 10x$
Combine like terms on both sides to simplify the inequality.
Get all $x$ terms on one side and constants on the other.
Isolate $x$ and prepare to divide by the coefficient of $x$ to solve.
Try solving on your own before revealing the answer!
Final Answer:
$x \geq 0$
The solution set is $[0, \infty)$ in interval notation.
We distributed, combined like terms, and isolated $x$ to find the solution set.
Q6. Solve the inequality:
4x + 1 < 4(x - 2)
Background
Topic: Linear Inequalities with Distribution
This question tests your ability to solve a linear inequality that requires distributing and isolating the variable.
Key Terms and Formulas:
Distributive Property: $a(b + c) = ab + ac$
Solving for $x$: Isolate $x$ on one side of the inequality.
Step-by-Step Guidance
Distribute $4$ on the right side:
$4x + 1 < 4x - 8$
Subtract $4x$ from both sides to get all $x$ terms on one side:
$1 < -8$
Analyze the resulting statement to determine if there are any solutions or if the solution set is empty.
Try solving on your own before revealing the answer!
Final Answer:
There is no solution because $1 < -8$ is never true.
The solution set is $\emptyset$ (the empty set).
Reference Table for Interval Notation and Graphs

This table summarizes how to write solution sets for inequalities using set notation, graph, and interval notation. Use it as a reference when expressing your answers.